x^2-122x+120=0

Solution for x^2-122x+120=0 equation:

x^2-122x+120=0

a = 1; b = -122; c = +120;
Δ = b2-4ac
Δ = -1222-4·1·120
Δ = 14404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14404}=\sqrt{4*3601}=\sqrt{4}*\sqrt{3601}=2\sqrt{3601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-122)-2\sqrt{3601}}{2*1}=\frac{122-2\sqrt{3601}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-122)+2\sqrt{3601}}{2*1}=\frac{122+2\sqrt{3601}}{2}
$